I need it within 15 minutes I will definitely upvote you PhysicsA torque of magnitude 5ON · m acts for 3seconds to start a small airplane propeller (I =12mr2) of length 1.2m and mass 10kg spinning.If treated as a rod rotated about its center,what is the final angular%3Dspeed of the propeller if we neglect the dragon it?A torque of magnitude 50N m acts for 3 seconds to start a small airplane propeller (I = mr?) oflength 1.2m and mass 10kg spinning. If treated as a rod rotated about its center, what is the final angularspeed of the propeller if we neglect the drag on it

Write the expression or the torque and substitute the required values to determine the angular…

A torque of magnitude 50N m acts for 3 seconds to start a small airplane propeller (I = }mr²) of length 1.2m and mass 10kg spinning. If treated as a rod rotated about its center, what is the final angular speed of the propeller if we neglect the drag on it

A torque of magnitude 50N m acts for 3 seconds to start a small airplane propeller (I = }mr²) of length 1.2m and mass 10kg spinning. If treated as a rod rotated about its center, what is the final angular speed of the propeller if we neglect the drag on it

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 67A

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While punting a football, a kicker rotates his leg about the hip joint. The moment of inertia of the leg is 3.75kgm2 and its rotational kinetic energy is 175 J. (a) What is the angular velocity of the leg? (b) What is the velocity of tip of the punter’s shoe if it is 1.05 m from the hip joint?
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Suppose a child gets off a rotating merry-go-round, Does the angular velocity of the merry-go-round increase, decrease, or remain the same if: (a) He jumps off radially? (b) He Jumps backward to land motionless? (c) He jumps straight up and hangs onto an overhead tree branch? (d) He jumps off forward, tangential to the edge? Explain your answers. (Refer to Figure 10.34).
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CHECK and THINK Our results give us a way to think about how a person might steer a unicycle. Consider the person, the unicycle, and the Earth as the system. No net torque acts on the system. Ignoring the motion of the Earth, Figure 13.37A shows the initial angular momentum of the system with the unicycle in motion: Li=Ltire. The person leans to his left so that the angular momentum of the tire rotates downward. The total angular momentum must still point to the right (Fig. 13.37B), so the angular momentum of the person must be upward to compensate. The persons angular velocity therefore points upward (parallel to his own angular momentum), and he is able to make a turn. Another way to analyze this situation is to exclude the Earth from the system and calculate the torque done by gravity. This approach is left as a homework problem. FIGURE 13.37 C Reanalyze the unicycles motion in Example 13.15 (page 382). This time, leave the Earth out of the system and explain how the torque exerted by gravity causes the unicycle to turn. Your explanation should involve a diagram.