A toy submarine of mass m = 0.730 kg moves around a submerged circular track of radius R = 1.77 m. The submarine's engine provides a constant propulsion force of F = 4.88 N. When the sub is in motion, it is subject to a viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0.s, the speed v (t) of the submarine at a later time t is given by F v(1) = -(1 – e-Cilm) C where e is the base of the natural logarithm. How much time has passed when the submarine's speed t = reaches 62% of its terminal value? What is the magnitude of the submarine's acceleration a at m/s2 a = this time?

A toy submarine of mass m = 0.730 kg moves around a submerged circular track of radius R = 1.77 m. The submarine's engine provides a constant propulsion force of F = 4.88 N. When the sub is in motion, it is subject to a viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0.s, the speed v (t) of the submarine at a later time t is given by F v(1) = -(1 – e-Cilm) C where e is the base of the natural logarithm. How much time has passed when the submarine's speed t = reaches 62% of its terminal value? What is the magnitude of the submarine's acceleration a at m/s2 a = this time?

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Description: A toy submarine of mass m = 0.730 kg moves around asubmerged circular track of radius R = 1.77 m. Thesubmarine's engine provides a constant propulsion force ofF = 4.88 N. When the sub is in motion, it is subject to aviscous drag force exerted by the

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 29P

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