A toy submarine of mass m = 0.830 kg moves around a submerged circular track of radius R = 1.97 m. The submarine's engine provides a constant propulsion force of F = 4.93 N. When the sub is in motion, it is subject to a viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = O s, the speed v (t) of the submarine at a later time t is given by F v() = (1 - e-Cilm) where e is the base of the natural logarithm. How much time has passed when the submarine's speed reaches 59% of its terminal value? What is the magnitude of the submarine's acceleration a at this time?

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter5: More Applications Of Newton’s Laws
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A toy submarine of mass m = 0.830 kg moves around a
submerged circular track of radius R = 1.97 m. The
submarine's engine provides a constant propulsion force of
F = 4.93 N. When the sub is in motion, it is subject to a
viscous drag force exerted by the water. This force is
proportional to the sub's speed; the proportionality factor is
C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the
speed v (t) of the submarine at a later time t is given by
v (1) = (1 - e-Cim)
%3D
where e is the base of the natural logarithm.
How much time has passed when the submarine's speed
reaches 59% of its terminal value?
t =
S
What is the magnitude of the submarine's acceleration a at
this time?
m/s?
a =
Transcribed Image Text:A toy submarine of mass m = 0.830 kg moves around a submerged circular track of radius R = 1.97 m. The submarine's engine provides a constant propulsion force of F = 4.93 N. When the sub is in motion, it is subject to a viscous drag force exerted by the water. This force is proportional to the sub's speed; the proportionality factor is C = 1.26 kg/s. Assuming it starts from rest at t = 0 s, the speed v (t) of the submarine at a later time t is given by v (1) = (1 - e-Cim) %3D where e is the base of the natural logarithm. How much time has passed when the submarine's speed reaches 59% of its terminal value? t = S What is the magnitude of the submarine's acceleration a at this time? m/s? a =
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