A triangular duct whose surfaces are all black has a length of L=0.69 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67×10® W/(m²K4) Lz=1.13 m, Tz=606 K L2=0.62 m, T2=433 K L3=0.84 m, T3=340 K

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Author:Kreith, Frank; Manglik, Raj M.
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Chapter8: Natural Convection
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A triangular duct whose surfaces are all black has a length of L=0.69 m. By considering
the details given below, calculate the total heat transfer rate by radiation from the
bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct,
in W.
o=5.67x10® W/(m²K4)
L1=1.13 m, T1=606 K
L2=0.62 m, T2=433 K
L3=0.84 m, T3=340 K
L2
L3
Transcribed Image Text:A triangular duct whose surfaces are all black has a length of L=0.69 m. By considering the details given below, calculate the total heat transfer rate by radiation from the bottom surface (Surface-1) to the other surfaces (Surface-2 and Surface-3) of the duct, in W. o=5.67x10® W/(m²K4) L1=1.13 m, T1=606 K L2=0.62 m, T2=433 K L3=0.84 m, T3=340 K L2 L3
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