A uniformly charged insulating rod of length 16.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of −7.50 µC.

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Chapter6: Gauss's Law
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Problem 22P: Find the electric flux through a rectangular area 3 cm x 2 cm between parallel plates where there is...
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A uniformly charged insulating rod of length 16.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of −7.50 µC.

 

(a) Find the magnitude of the electric field (in N/C) at o, the center of the semicircle,
| N/C
(b) Find the direction of the electric field at 0, the center of the semicircle.
to the left
O to the right
O upward
downward
O into the page
O out of the page
(c) What if? What would be the magnitude
the electric field (in N/C) at o if the
half
the semicircle carrie
total charge
-7.50 µC and the botto
insulated
top half,
a total charge of +7.50 µC?
N/C
(d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
O to the left
O to the right
O upward
O downward
O into the page
O out of the page
Transcribed Image Text:(a) Find the magnitude of the electric field (in N/C) at o, the center of the semicircle, | N/C (b) Find the direction of the electric field at 0, the center of the semicircle. to the left O to the right O upward downward O into the page O out of the page (c) What if? What would be the magnitude the electric field (in N/C) at o if the half the semicircle carrie total charge -7.50 µC and the botto insulated top half, a total charge of +7.50 µC? N/C (d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? O to the left O to the right O upward O downward O into the page O out of the page
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