A university claims that their employment rate directly after graduation is 80%. In a sample of 700 graduates, 609 found to have gained employment directly after graduation. Test the claim that the university's employment rate after graduation is significantly different than 80% at the 0.01 significance level. The null and alternative hypothesis would be: H0:μ≥0.8H0:μ≥0.8 H1:μ<0.8H1:μ<0.8 H0:μ≤0.8H0:μ≤0.8 H1:μ>0.8H1:μ>0.8 H0:p≥0.8H0:p≥0.8 H1:p<0.8H1:p<0.8 H0:p=0.8H0:p=0.8 H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8 H1:p>0.8H1:p>0.8 H0:μ=0.8H0:μ=0.8 H1:μ≠0.8H1:μ≠0.8 The test is: left-tailed right-tailed two-tailed The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

A university claims that their employment rate directly after graduation is 80%. In a sample of 700 graduates, 609 found to have gained employment directly after graduation. Test the claim that the university's employment rate after graduation is significantly different than 80% at the 0.01 significance level. The null and alternative hypothesis would be: H0:μ≥0.8H0:μ≥0.8 H1:μ<0.8H1:μ<0.8 H0:μ≤0.8H0:μ≤0.8 H1:μ>0.8H1:μ>0.8 H0:p≥0.8H0:p≥0.8 H1:p<0.8H1:p<0.8 H0:p=0.8H0:p=0.8 H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8 H1:p>0.8H1:p>0.8 H0:μ=0.8H0:μ=0.8 H1:μ≠0.8H1:μ≠0.8 The test is: left-tailed right-tailed two-tailed The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

See similar textbooks

Similar questions

An educational report asserts that 70% of all young adults start planning their career at the age of 18. In a sample of 1000 adults, 744 started their career plans at the age of 18. Test whether the true proportion of all young adults who began planning their career at the age of 18 is more than 70% at the 5% significance level.State the null hypothesis and the alternative hypothesis. Group of answer choices H0: p = 0.7 vs. Ha: p ≠ 0.7 H0: p = 0.7 vs. Ha: p < 0.7 H0: p = 0.7 vs. Ha: p ≥ 0.7 H0: p = 0.7 vs. Ha: p ≤ 0.7 H0: p = 0.7 vs. Ha: p > 0.7
A well-known brokerage firm executive claimed that 40% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 500 people, 35% of them said they are confident of meeting their goals.Test the claim that the proportion of people who are confident is smaller than 40% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ≥0.4 H1:μ<0.4 H0:p≤0.4 H1:p>0.4 H0:p=0.4 H1:p≠0.4 H0:p≥0.4 H1:p<0.4 H0:μ=0.4 H1:μ≠0.4 H0:μ≤0.4 H1:μ>0.4 The test is: two-tailed left-tailed right-tailed The test statistic is: (to 3 decimals)The p-value is: (to 4 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
A fast-food restaurant claims that a small order of french fries contains 120 calories. A nutritionist is concerned that the true average calorie count is higher than that. The nutritionist randomly selects 35 small orders of french fries and determines their calories. The resulting sample mean is 155.6 calories, and the pp-value for the hypothesis test is 0.00093. Which of the following is a correct interpretation of the p-value? A)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more. B) If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or less. C)If the population mean is 120 calories, the p -value of 0.00093 is the probability of observing a sample mean of 155.6 calories or more, or a sample mean of 84.4 calories or less. .D)If the population mean is 155.6 calories, the p -value of 0.00093…
A concerned group of citizens wanted to know if the proportion of armed robberies in Texas was different in 2011 than in 2010. Their research showed that of the 113,231 violent crimes in Texas in 2010, 7,622 of them were armed robberies. In 2011, 7,439 of the 104,873 violent crimes were in the armed robbery category. Test at a 5% significance level.a) The null and alternative hypothesis would be: �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010<�2011 �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010<�2011 b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p = d) Make a decision. Fail to reject the null hypothesis Reject the null hypothesis e) Write the conclusion. There is not sufficient evidence to support the claim that the proportion of armed robberies is different in 2011 than 2010. There is sufficient evidence to support the claim that the…
If, in a one-tail hypothesis test where H0 is only rejected in the upper tail, the p-value=0.6792 and ZSTAT=−0.47,what is the statistical decision if the null hypothesis is tested at the 0.07 level of significance? What is the statistical decision? Since the p-value is Less than or Greater than or equal to a= , Reject , Do not reject H0.
Is there a significant difference in the unemployment rates among Hispanic and white adults in the state of Texas? Based on data collected by the Texas Workforce Commission, 4.6% of 640 randomly selected Hispanic adults are unemployed while 2.8% of 780 randomly selected white adults are unemployed. Does this data provide statistically significant evidence that there is a difference in the unemployment rates between the two groups? a) State the null hypothesis (H0) and the alternative hypothesis (Ha ) for the significance test and the conditions b) assume the conditions are satisfied, identify the test statistic (z or t?) to be used, and show the formula for the test statistic, and enter the appropriate values in the formula. (don’t calculate the test statistic here.) c) Assume that the standard error of the differences in proportions is SE = 0.00995. Using this SE, calculate the value of the test statistic (which you set up in part (b) and find the p-value d) Using a significance…
A concerned group of citizens wanted to know if the proportion of armed robberies in Texas was different in 2011 than in 2010. Their research showed that of the 113,231 violent crimes in Texas in 2010, 7,622 of them were armed robberies. In 2011, 7,439 of the 104,873 violent crimes were in the armed robbery category. Test at a 5% significance level.a) The null and alternative hypothesis would be: H0:p2010=p2011H1:p2010<p2011 H0:μ2010=μ2011H1:μ2010<μ2011 H0:p2010=p2011H1:p2010≠p2011 H0:μ2010=μ2011H1:μ2010≠μ2011 H0:p2010=p2011H1:p2010>p2011 H0:μ2010=μ2011H1:μ2010>μ2011 b) Determine the test statistic. Round to two decimals.z=c) Find the p-value and round to 4 decimals.p =
A study is conducted to determine if bus ridership in a large city is higher during the afternoon rush hours than morning rush hours. The transit authority randomly selects nine buses and on a given day counts the number of riders at 7:45 AM and 4:45 PM. The results are shown below. Conduct an appropriate hypothesis test using 0.05 level of significance. Morning 43 43 37 25 47 42 48 55 52 Afternoon 41 49 44 32 46 55 53 52 50 If the null hypothesis is rejected, what is the actual risk of having made a wrong decision? Enter the answer in percent and round it to the nearest integer. For example if the probability of wrong decision is 0.155, multiply it by 100 to change it to percent (100*0.155=15.5), and then round it to the nearest integer which would be 16. Enter 16 in the answer text box. If there is not enough information available to compute the probability enter “N” in the answer text box Your answer is (percent in integer…