men who own cats at the 0.01 significance level. e null and alternative hypothesis would be: 0:HM = HF_Ho:PM = PF Ho:µM = µf_Ho:µM 1:HM > µp_H1:pM > PF H1:µM Hf H1:µM < µp H:PM < PF H:PM † PF. µp Ho:PM = Pf Ho:PM = PF e test is: "o-tailed left-tailed right-tailed sed on a sample of 40 men, 45% owned cats sed on a sample of 40 women, 55% owned cats e test statistic is: |(to 2 decimals) e p-value is: |(to 2 decimals) sed on this we: O Reject the null hypothesis

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 58E: What is meant by the sample space of an experiment?
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Test the claim that the proportion of men who own cats is significantly different than the proportion of
women who own cats at the 0.01 significance level.
The null and alternative hypothesis would be:
Ho:HM
µf Ho:PM = Pf Ho:HM = HF Họ:µM
µf Ho:PM = PF Ho:PM
PF
H1: HM > µF H1:PM > PF H1:µM + HF_H1:HM < µp_Hj:PM < PF H1:PM + PF
The test is:
two-tailed left-tailed right-tailed
Based on a sample of 40 men, 45% owned cats
Based on a sample of 40 women, 55% owned cats
The test statistic is:
(to 2 decimals)
The p-value is:
(to 2 decimals)
Based on this we:
O Reject the null hypothesis
Fail to reject the null hypothesis
Transcribed Image Text:Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.01 significance level. The null and alternative hypothesis would be: Ho:HM µf Ho:PM = Pf Ho:HM = HF Họ:µM µf Ho:PM = PF Ho:PM PF H1: HM > µF H1:PM > PF H1:µM + HF_H1:HM < µp_Hj:PM < PF H1:PM + PF The test is: two-tailed left-tailed right-tailed Based on a sample of 40 men, 45% owned cats Based on a sample of 40 women, 55% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis Fail to reject the null hypothesis
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