(a) Use the definition to prove that f(x) = is uniformly continuous on the x +1 domain [0, 00). x- 2 (b) Use the definition to prove that the function f(x): is continuous at a = 2. x+2

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.CR: Chapter 3 Review
Problem 12CR: Determine whether each of the following statements is true or false and explain why. The derivative...
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Real Analysis 1
tihuous on the set D(k) = {x € F:0<x}.
Expert Answer
Step 1
Uniformly Continuous
Definition: A function fis said to be uniformly continuous on R if, for every ɛ > 0, there exists & >0 such that
x, y ER with r- y| < 8, then |f (x) – f (v)| < e
4. (a) Here, we have to show f (x) = sin x is uniformly continuous for x ER
For this, we shall use the definition of uniform continuous function.
Step 2
Let ɛ > 0. Choose & = ɛ.
Transcribed Image Text:tihuous on the set D(k) = {x € F:0<x}. Expert Answer Step 1 Uniformly Continuous Definition: A function fis said to be uniformly continuous on R if, for every ɛ > 0, there exists & >0 such that x, y ER with r- y| < 8, then |f (x) – f (v)| < e 4. (a) Here, we have to show f (x) = sin x is uniformly continuous for x ER For this, we shall use the definition of uniform continuous function. Step 2 Let ɛ > 0. Choose & = ɛ.
1. Choose and work either (a) or (b), NOT BOTH.
(a) Use the definition to prove that f(x) =
domain [0, 00).
is uniformly continuous on the
x +1
|
X-2
(b) Use the definition to prove that the function f(x) =
is continuous at a = 2.
x+2
2. Choose and work either a) or b), NOT BOTH.
1
NOT uniforml
continuouus on the
Transcribed Image Text:1. Choose and work either (a) or (b), NOT BOTH. (a) Use the definition to prove that f(x) = domain [0, 00). is uniformly continuous on the x +1 | X-2 (b) Use the definition to prove that the function f(x) = is continuous at a = 2. x+2 2. Choose and work either a) or b), NOT BOTH. 1 NOT uniforml continuouus on the
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