A voltaic cell utilizes the following reaction: 4FE²+(aq) + O2(g)+4H*(aq)→4Fe3+(aq) + 2H2O(1) Correct The standard emf is found by subtracting the standard reduction potential at the anode from the standard reduction potential at the cathode. The oxidation of iron at the anode corresponds to a standard reduction potential of 0.77 V, and the reduction of oxygen at the cathode corresponds to a standard reduction potential of 1.23 V such that E cell E° red (cathode) – E red (anode) 1.23 V – 0.77 V %3D 0.46 V Part B What is the emf of this cell when (Fe²+] = 1.8 M , [Fe³+] = 1.2x10-2 M , Po, = 0.55 atm , and the pH of the solution in the cathode compartment is 3.2? Express your answer in volts using two significant figures. ?

Chemistry: Principles and Practice
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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.102QE: At 298 K, the solubility product constant for Pb(IO3)2 is 2.6 1013, and the standard reduction...
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A voltaic cell utilizes the following reaction:
4FE2+(aq) + O2 (g)+4H*(aq)→4Fe³+ (aq) +2H2O(1)
Correct
The standard emf is found by subtracting the standard reduction potential at the anode from the standard reduction
potential at the cathode. The oxidation of iron at the anode corresponds to a standard reduction potential of 0.77
V, and the reduction of oxygen at the cathode corresponds to a standard reduction potential of 1.23 V such that
E° cll
E° red (cathode) – F red (anode)
1.23 V – 0.77 V
0.46 V
Part B
What is the emf of this cell when [Fe2+] = 1.8 M [Fe³+] = 1.2x10-2 M , Po, = 0.55 atm , and the pH of the solution in the
cathode compartment is 3.2?
Express your answer in volts using two significant figures.
?
E =
V
Submit
Request Answer
Transcribed Image Text:A voltaic cell utilizes the following reaction: 4FE2+(aq) + O2 (g)+4H*(aq)→4Fe³+ (aq) +2H2O(1) Correct The standard emf is found by subtracting the standard reduction potential at the anode from the standard reduction potential at the cathode. The oxidation of iron at the anode corresponds to a standard reduction potential of 0.77 V, and the reduction of oxygen at the cathode corresponds to a standard reduction potential of 1.23 V such that E° cll E° red (cathode) – F red (anode) 1.23 V – 0.77 V 0.46 V Part B What is the emf of this cell when [Fe2+] = 1.8 M [Fe³+] = 1.2x10-2 M , Po, = 0.55 atm , and the pH of the solution in the cathode compartment is 3.2? Express your answer in volts using two significant figures. ? E = V Submit Request Answer
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