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A weapons manufacturer uses a liquid propellant that can get mixed with another liquid to produce a contaminated cartridge. A statistician found that 24% of the cartridges in the particular lot were contaminated. Suppose you randomly sample (without replacement) gun cartridges from this lot until you find a contaminated one. Let x be the number of cartridges sampled until a contaminated one is found. It is known that the probability distribution for x is given by the formula shown below. Complete parts a through c. p(x) = (0.24)(0.76)* -1, x= 1, 2 ,3 . a. Find p(1). Interpret this result. p(1) = 24 (Round to three decimal places as needed.) What is the correct interpretation for p(1)? O A. This value is the probability that one would encounter a contaminated cartridge in one hundred trials. B. This value is the probability that one would encounter a contaminated cartridge on the first trial. O C. This value is the probability that one would encounter a non-contaminated cartridge on the first trial. b. Find p(6). Interpret this result. p(6) = .048 (Round to three decimal places as needed.)

A weapons manufacturer uses a liquid propellant that can get mixed with another liquid to produce a contaminated cartridge. A statistician found that 24% of the cartridges in the particular lot were contaminated. Suppose you randomly sample (without replacement) gun cartridges from this lot until you find a contaminated one. Let x be the number of cartridges sampled until a contaminated one is found. It is known that the probability distribution for x is given by the formula shown below. Complete parts a through c. p(x) = (0.24)(0.76)* -1, x= 1, 2 ,3 . a. Find p(1). Interpret this result. p(1) = 24 (Round to three decimal places as needed.) What is the correct interpretation for p(1)? O A. This value is the probability that one would encounter a contaminated cartridge in one hundred trials. B. This value is the probability that one would encounter a contaminated cartridge on the first trial. O C. This value is the probability that one would encounter a non-contaminated cartridge on the first trial. b. Find p(6). Interpret this result. p(6) = .048 (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A weapons manufacturer uses a liquid propellant that can get mixed with another liquid to produce a contaminated cartridge. A statistician found that 24% of the cartridges in the particular lot were contaminated. Suppose you randomly sample (without replacement) gun cartridges from this lot until you find a contaminated one. Let x be the number of cartridges sampled until a contaminated one is found. It is known that the probability distribution for x is given by the formula shown below. Complete parts a through c. p(x) = (0.24)(0.76)*-1,x=1, 2 ,3 ,.. ..... a. Find p(1). Interpret this result. p(1) = .24 (Round to three decimal places as needed.) What is the correct interpretation for p(1)? O A. This value is the probability that one would encounter a contaminated cartridge in one hundred trials. B. This value is the probability that one would encounter a contaminated cartridge on the first trial. O C. This value is the probability that one would encounter a non-contaminated cartridge on the first trial. b. Find p(6). Interpret this result. p(6) = .048 (Round to three decimal places as needed.) EGO
Transcribed Image Text:A weapons manufacturer uses a liquid propellant that can get mixed with another liquid to produce a contaminated cartridge. A statistician found that 24% of the cartridges in the particular lot were contaminated. Suppose you randomly sample (without replacement) gun cartridges from this lot until you find a contaminated one. Let x be the number of cartridges sampled until a contaminated one is found. It is known that the probability distribution for x is given by the formula shown below. Complete parts a through c. p(x) = (0.24)(0.76)*-1,x=1, 2 ,3 ,.. ..... a. Find p(1). Interpret this result. p(1) = .24 (Round to three decimal places as needed.) What is the correct interpretation for p(1)? O A. This value is the probability that one would encounter a contaminated cartridge in one hundred trials. B. This value is the probability that one would encounter a contaminated cartridge on the first trial. O C. This value is the probability that one would encounter a non-contaminated cartridge on the first trial. b. Find p(6). Interpret this result. p(6) = .048 (Round to three decimal places as needed.) EGO
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