a) What is factor of safety (F.S.) and state two application areas. b) Under shear stress studies, explain complementary property of shear. c) The joint is fastened together using two bolts. Determine the required diameter of the bolts if the failure shear stress for the bolts is Tfail = 350 MPa. Use a factor of safety for shear of F.S. = 2.5.

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Chapter12: Static Equilibrium And Elasticity
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Problem 12.28P: Assume Youngs modulus for bone is 1.50 1010 N/m2. The bone breaks if stress greater than 1.50 108...
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Question four
a) What is factor of safety (F.S.) and state two application areas.
b) Under shear stress studies, explain complementary property of shear.
c) The joint is fastened together using two bolts. Determine the required diameter
of the bolts if the failure shear stress for the bolts is Tfail = 350 MPa. Use a factor of
safety for shear of F.S. = 2.5.
30 mm.
80 kN
30 mm
40 kN
40 kN
Transcribed Image Text:Question four a) What is factor of safety (F.S.) and state two application areas. b) Under shear stress studies, explain complementary property of shear. c) The joint is fastened together using two bolts. Determine the required diameter of the bolts if the failure shear stress for the bolts is Tfail = 350 MPa. Use a factor of safety for shear of F.S. = 2.5. 30 mm. 80 kN 30 mm 40 kN 40 kN
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