(a) What is the magritude of the tangential acceleration of a bug on the rim of an 11.0-in.-diameter disk e the disk accelerates uniformly from rest to an angular speed of 80.0 rev/min in 4.90 s?m/s?(b) When the disk is at ita final speed, what is the magnitude of the tangential velocity of the bug?m/s(e) One secord ater the bug starts tram rest, what is the magntude of its tangential acceleration?m/s?(a) One second after the bug starts from rest, what is the magnitude of its centripetal acceleration?Ims(e) One second after the bug starts from rest, what is ts total acceeration? (Take the positive direction to be in the direction of motion)magnitudemstdirectionfrom the radially inwerd directionuok

Given Information,Diameter of the rim D =11 inchs =0.279 metersRadius R =0.2792=initial Angular…

Answered: (a) What is the magnitude of the…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 103A

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(a) What is the magritude of the tangential acceleration of a bug on the rim of an 11.0-in.-diameter disk e the disk accelerates uniformly from rest to an angular speed of 80.0 rev/min in 4.90 s?
m/s?
(b) When the disk is at ita final speed, what is the magnitude of the tangential velocity of the bug?
m/s
(e) One secord ater the bug starts tram rest, what is the magntude of its tangential acceleration?
m/s?
(a) One second after the bug starts from rest, what is the magnitude of its centripetal acceleration?
Ims
(e) One second after the bug starts from rest, what is ts total acceeration? (Take the positive direction to be in the direction of motion)
magnitude
mst
direction
from the radially inwerd direction
uok

Expert Solution

Step 1

$Given Information, Diameter of the rim D = 11 inchs = 0.279 meters Radius R = \frac{0.279}{2} = initial Angular Velocity ω_{1} = 0 Final Angular Velocity ω_{2} = \frac{2 π 80}{60} = 8.377 rad / s Time t = 4.9 seconds$

Part a

$We have, ω_{2} = ω_{1} + αt 8.377 = 0 + α (4.9) α = 1.709 rad / s^{2} Tangential Acceleration = Rα = \frac{0.279}{2} \times 1.709 = 0.2384 m / s^{2}$

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