a)    x < 30 z < (b)    19 < x (Fill in the blank. A blank is represented by _____.) _____ < z (c)    32 < x < 35 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.) _____ < z < _____

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Exponential And Logarithmic Functions
Section5.5: Exponential And Logarithmic Models
Problem 4ECP
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Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean μ = 27.0 kilograms and standard deviation σ = 3.1 kilograms. Let x be the weight of a fawn in kilograms.

 

For parts (a), (b), and (c), convert the x intervals to z intervals. (For each answer, enter a number. Round your answers to two decimal places.)

(a)

   x < 30
z <

(b)

   19 < x (Fill in the blank. A blank is represented by _____.)

_____ < z



(c)

   32 < x < 35 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.)

_____ < z < _____

first blank    
second blank    


For parts (d), (e), and (f), convert the z intervals to x intervals. (For each answer, enter a number. Round your answers to one decimal place.)

(d)

   −2.17 < z (Fill in the blank. A blank is represented by _____.)

_____ < x



(e)

   z < 1.28
x <

(f)

   −1.99 < z < 1.44 (Fill in the blanks. A blank is represented by _____. There are two answer blanks.)

_____ < x < _____

first blank    
second blank    

(g)

If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
Yes. This weight is 4.19 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.Yes. This weight is 2.10 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.     No. This weight is 4.19 standard deviations below the mean; 14 kg is a normal weight for a fawn.No. This weight is 4.19 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.No. This weight is 2.10 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.

(h)

If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
It would have a z of 0.It would have a negative z, such as −2.     It would have a large positive z, such as 3.
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