A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise. def is_leap_year(user_year) My Code: def is_leap_year(user_year): if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)): print("{} is a leap year.".format(user_year)) else: print("{} is not a leap year.".format(user_year)) if __name__ == '__main__': user_year = int(input()) print(is_leap_year(user_year)) My output: 1712 is a leap year. None I dont know why the 'none' is being put out and for some reason it wont compute the other input values.
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712, and 2016.
Write a program that takes in a year and determines whether that year is a leap year.
Ex: If the input is: 1712
output: 1712 is a leap year.
input: 1913
output: 1913 is not a leap year.
Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.
def is_leap_year(user_year)
My Code:
def is_leap_year(user_year):
if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):
print("{} is a leap year.".format(user_year))
else:
print("{} is not a leap year.".format(user_year))
if __name__ == '__main__':
user_year = int(input())
print(is_leap_year(user_year))
My output: 1712 is a leap year. None
I dont know why the 'none' is being put out and for some reason it wont compute the other input values.
This method is not correct:
# Modified Code
def is_leap_year(user_year):
if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):
print(user_year," is a leap year.")
else:
print(user_year," is not a leap year.")
is_leap_year(1712)
is_leap_year(1913)
is_leap_year(1600)
is_leap_year(1900)
The system checks the function with one variable at the time, and this function causes 4 outputs when the system is only looking for 1. (see picture)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
