A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.bool IsLeapYear(int userYear) Note: This is a lab from a previous chapter that now requires the use of a function. #include <iostream>using namespace std; bool IsLeapYear(int userYear) {int userYear;bool isLeapYear;}if (userYear % 100 == 0) {if (userYear % 400 == 0) {isLeapYear = true;cout << userYear << " is a leap year." << endl;}else {isLeapYear = false;cout << userYear << " is not a leap year." << endl;}}else {if (userYear % 4 == 0) {isLeapYear = true;cout << userYear << " is a leap year." << endl;}else {isLeapYear = false;cout << userYear << " is not a leap year." << endl;}}return isLeapYear}int main () {int userYear;cin >> userYear;if (isLeapYear(userYear) == true) {cout << userYear << " is a leap year" << endl;}else {cout << userYear << " is not a leap year" << endl;}return 0 } Please help me with this problem using c++.
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712, and 2016.
Write a
Ex: If the input is:
1712
the output is:
1712 is a leap year.
Ex: If the input is:
1913
the output is:
1913 is not a leap year.
Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.
bool IsLeapYear(int userYear)
Note: This is a lab from a previous chapter that now requires the use of a function.
#include <iostream>
using namespace std;
bool IsLeapYear(int userYear) {
int userYear;
bool isLeapYear;
}
if (userYear % 100 == 0) {
if (userYear % 400 == 0) {
isLeapYear = true;
cout << userYear << " is a leap year." << endl;
}
else {
isLeapYear = false;
cout << userYear << " is not a leap year." << endl;
}
}
else {
if (userYear % 4 == 0) {
isLeapYear = true;
cout << userYear << " is a leap year." << endl;
}
else {
isLeapYear = false;
cout << userYear << " is not a leap year." << endl;
}
}
return isLeapYear
}
int main () {
int userYear;
cin >> userYear;
if (isLeapYear(userYear) == true) {
cout << userYear << " is a leap year" << endl;
}
else {
cout << userYear << " is not a leap year" << endl;
}
return 0
}
Please help me with this problem using c++.
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