A) You hold glider AA of mass 0.125 kgkg and glider BB of mass 0.375 kgkg at rest on an air track with a compressed spring of negligible mass between them. When you release the gliders, the spring pushes them apart. Once the gliders are no longer in contact with the spring, glider AA is moving to the right at 0.600 m/sm/s. What is the velocity (magnitude and direction) of glider BB at this time? B) Glider AA moving to the right at 0.600 m/sm/s then collides head-on with a third glider CC of mass 0.750 kgkg that is moving to the left at 0.400 m/sm/s. After this collision, glider CC is moving to the left at 0.150 m/sm/s. What is the velocity (magnitude and direction) of glider AA after this collision? C) Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kgkg, is moving at 6.00 m/sm/s to the east just before the collision and at 3.00 m/sm/s to the west just after the collision. Buffy, of mass 55.0 kgkg, is moving at 3.50 m/sm/s to the east just after the collision. Find Buffy's velocity (magnitude and direction) just before the collision.

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter11: Collisions
Section: Chapter Questions
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A) You hold glider AA of mass 0.125 kgkg and glider BB of mass 0.375 kgkg at rest on an air track with a compressed spring of negligible mass between them. When you release the gliders, the spring pushes them apart. Once the gliders are no longer in contact with the spring, glider AA is moving to the right at 0.600 m/sm/s. What is the velocity (magnitude and direction) of glider BB at this time?

B) Glider AA moving to the right at 0.600 m/sm/s then collides head-on with a third glider CC of mass 0.750 kgkg that is moving to the left at 0.400 m/sm/s. After this collision, glider CC is moving to the left at 0.150 m/sm/s. What is the velocity (magnitude and direction) of glider AA after this collision?

C) Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kgkg, is moving at 6.00 m/sm/s to the east just before the collision and at 3.00 m/sm/s to the west just after the collision. Buffy, of mass 55.0 kgkg, is moving at 3.50 m/sm/s to the east just after the collision. Find Buffy's velocity (magnitude and direction) just before the collision.

D)What is the change in the velocity of Madeleine during the collision? Take east to be the positive direction.

E) What is the change in the velocity of Buffy during the collision? Take east to be the positive direction.
 
F) Who has the greater magnitude of velocity change: more massive Madeleine or less massive Buffy?
 
G) A 2.40 kgkg stone is sliding in the +x+x-direction on a horizontal, frictionless surface. It collides with a 4.00 kgkg stone at rest. After the collision the 2.40 kgkg stone is moving at 3.60 m/sm/s at an angle of 30.0∘∘ measured from the +x+x-direction toward the +y+y-direction and the 4.00 kgkg stone is moving at an angle of 45.0∘∘ measured from the +x+x-direction toward the −y−y-direction. What is the yy-component of momentum of the 2.40 kgkg stone after the collision?
 
H) What must be the yy-component of momentum of the 4.00 kgkg stone after the collision?
 
I) What is the speed of the 4.00 kgkg stone after the collision?
 
J) What is the x-component of the total momentum of the two stones after the collision?
 
K) What is the speed of the 2.40 kgkg stone before the collision?
 
L) A hockey puck of mass mm is moving in the +x+x-direction at speed vP1vP1 on a frictionless, horizontal surface. It collides with a stone of mass 2mm that is initially at rest. After the collision the hockey puck is moving at an angle θθ measured from the +x+x-direction toward the +y+y-direction and the stone is moving at the same angle θθ but measured from the +x+x-direction toward the −y−y-direction. In order for the yy-component of momentum to be conserved, what must be the ratio of the final speed vS2vS2 of the stone to the final speed vP2vP2 of the hockey puck?
 
M) Use conservation of the x-component of momentum to find vS2vS2 in terms of v1v1 and θθ, where v1=vP1v1=vP1.
 
N) Use conservation of the x-component of momentum to find vP2vP2 in terms of v1v1 and θθ, where v1=vP1v1=vP1.
 
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