a. 8.7 g + 15.43 g + 19 g = 43.13 g b. 4.32 cm X 1.7 cm = 7.344 cm² c. 853.2 L - 627.443 L = 225.757 L d. 38.742 m² ÷ 0.421 m = 92.023 75 m 1 3 32.431 914 m³ 103.770 m³ e. 5.40 m X 3.21 m X 1.871 m f. 5.47 m³ + 11 m³ + 87.300 m³ = 3 3 3 =

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 44E: a. How many kilograms are in 1 teragram? b. How many nanometers are in 6.50 x 102 terameters? c. How...
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*59. Round off each of the answers correctly.
a. 8.7 g +15.43 g + 19 g = 43.13 g
b. 4.32 cm X 1.7 cm
7.344 cm²
-
c. 853.2 L - 627.443 L = 225.757 L
d. 38.742 m² ÷ 0.421 m =
= 92.023 75 m
=
3
32.431 914 m
e. 5.40 m X 3.21 m X 1.871 m
3
3
f. 5.47 m³ + 11 m³ + 87.300 m³= 103.770 m³
g
71.
72.
Transcribed Image Text:*59. Round off each of the answers correctly. a. 8.7 g +15.43 g + 19 g = 43.13 g b. 4.32 cm X 1.7 cm 7.344 cm² - c. 853.2 L - 627.443 L = 225.757 L d. 38.742 m² ÷ 0.421 m = = 92.023 75 m = 3 32.431 914 m e. 5.40 m X 3.21 m X 1.871 m 3 3 f. 5.47 m³ + 11 m³ + 87.300 m³= 103.770 m³ g 71. 72.
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