a. Check the adequacy of the beam for flexure (2= 1.67) and shear (Cy= 1.0 and £2,= 1.5). b. Check if the mid-span deflection of the beam is satisfactory for the service assuming that the maximum permissible value is Alim - L/300. Material: $355 Fy=355 N/mm² Fu=510 N/mm² E= 200000 N/mm²
a. Check the adequacy of the beam for flexure (2= 1.67) and shear (Cy= 1.0 and £2,= 1.5). b. Check if the mid-span deflection of the beam is satisfactory for the service assuming that the maximum permissible value is Alim - L/300. Material: $355 Fy=355 N/mm² Fu=510 N/mm² E= 200000 N/mm²
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
A beam shown below is laterally supported at its ends and at the point in which the concentrated load exist.
![a. Check the adequacy of the beam for flexure (2b = 1.67) and shear (Cy=1.0 and £2,= 1.5).
b. Check if the mid-span deflection of the beam is satisfactory for the service assuming that the maximum
permissible value is Alim = L/300.
Material: $355
240
HE280B
3.2
m
137.5
Fy=355 N/mm²
P = 200 KN
B
* 3.2
m
200
62.5
=
1 PL³
107.3 EI
V [kN]
M [kNm]
Fu=510 N/mm² E = 200000 N/mm²
tw
11
bę
I-I Section
b₁
1+
1 ht
6 b.t
HE280B
A
Ix
Iy
d
be
tw
h
Sx
Sy
Zx
Zy
Cw
J
131.4 cm²
= 19270 cm¹
= 6595 cm²
= 280 mm
= 280 mm
= 18 mm
- 10.5 mm
=
= 196 mm
= 1376 cm³
= 471 cm³
- 1534 cm³
= 717.6 cm³
= 12.1 cm
= 7.09 cm
=
- 1130000 cm6
=
- 143.7 cm²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd16c010b-e3a4-43fc-8f0e-3b236621d214%2F97433135-5bb3-4c30-b2c4-a4211ce3de41%2Fb2cm02_processed.png&w=3840&q=75)
Transcribed Image Text:a. Check the adequacy of the beam for flexure (2b = 1.67) and shear (Cy=1.0 and £2,= 1.5).
b. Check if the mid-span deflection of the beam is satisfactory for the service assuming that the maximum
permissible value is Alim = L/300.
Material: $355
240
HE280B
3.2
m
137.5
Fy=355 N/mm²
P = 200 KN
B
* 3.2
m
200
62.5
=
1 PL³
107.3 EI
V [kN]
M [kNm]
Fu=510 N/mm² E = 200000 N/mm²
tw
11
bę
I-I Section
b₁
1+
1 ht
6 b.t
HE280B
A
Ix
Iy
d
be
tw
h
Sx
Sy
Zx
Zy
Cw
J
131.4 cm²
= 19270 cm¹
= 6595 cm²
= 280 mm
= 280 mm
= 18 mm
- 10.5 mm
=
= 196 mm
= 1376 cm³
= 471 cm³
- 1534 cm³
= 717.6 cm³
= 12.1 cm
= 7.09 cm
=
- 1130000 cm6
=
- 143.7 cm²
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