a. disulfur tetrafluoride Sy b. carbon trioxide Co c. nitrogen pentoxide NO d. nitrogen tribromide Brz e. dinitrogen heptachloride f. carbon tetrachloride W₂C₂ CC14 C 3+ g. hydrogen monochloride HCL h. trihydrogen monophosphide HP i. dihydrogen monoxide H₂O 1 и br 3²x² = W/Br3 3+ 1- - соз C 4+ cl NO 5+ H cl # CL = (HCI) it {ccl4 H P = 3- NOS =/H₂₂₂ P +3

Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter8: Chemical Composition
Section: Chapter Questions
Problem 94AP
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Write the formualas for the covalent compound. Are they correct answer? Can you explain to me about the criss-cross method, charge ion, and polyatomic ion on this each questions to show the step by step?

a. disulfur tetrafluoride
b. carbon trioxide Co
c. nitrogen pentoxide NO
N Br
d. nitrogen tribromide WB ³² X ² = √W Brz
e. dinitrogen heptachloride W₂CL₂
CCH
g. hydrogen monochloride HCL
h. trihydrogen monophosphide H₂P
i. dihydrogen monoxide
HO
f. carbon tetrachloride
H
it.
S₂ Fy
2
=
H₂O
LO
3+
40 = CO₂
NO=
5+
디
& C = CCl4
4+
HCL = H.CI/
cl
NOS
´H P = H₂ P
3
it
3
Transcribed Image Text:a. disulfur tetrafluoride b. carbon trioxide Co c. nitrogen pentoxide NO N Br d. nitrogen tribromide WB ³² X ² = √W Brz e. dinitrogen heptachloride W₂CL₂ CCH g. hydrogen monochloride HCL h. trihydrogen monophosphide H₂P i. dihydrogen monoxide HO f. carbon tetrachloride H it. S₂ Fy 2 = H₂O LO 3+ 40 = CO₂ NO= 5+ 디 & C = CCl4 4+ HCL = H.CI/ cl NOS ´H P = H₂ P 3 it 3
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