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Does the following molecule obey
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- 10.11/ A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy is heated to 250°C (480°F), at which temperature it is entirely an a-phase solid solution . The alloy is to be melted to the extent that 50% of the speci- men is liquid, the remainder being the a phase. This may be accomplished either by heating the alloy or changing its composi- tion while holding the temperature con- stant. (a) To what temperature must the speci- men be heated? (b) How much tin must be added to the 1.5-kg specimen at 250°C to achieve this state? 10.15) A magnesium-lead alloy of mass 5.5 ka consists of a solid a phase that has a compo- sition that is just slightly below the solubility limit at 200°C (390°F). (a) What mass of lead is in the alloy? (b) If the alloy is heated to 350°C (660°F). how much more lead may be dissolved in the a phase without exceeding the solubility limit of this phase? 10.27 A hypothetical A-B alloy of composition 55 wt% B-45 wt% A at some temperature is found to consist of mass…image https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/gen_chem/eo.html ^ tablehttps://m.youtube.com/watch?v=vM1SP346XBc&list=PLeJOSNLNZfHubfLdq0kOayASeUllMOGn4&index=4 I watched this the lecture video over and over and I am allowed to work with someone but I am having trouble with part B and I provided the YouTube link of the data or video attached to this lab
- 1-Pentanol to 1-bromopentane Chemicals: - 60ml Conc. Sulfuric Acid - 100ml Saturated Sodium bicarbonate - 65ml 1-Pentanol - 78g sodium bromide - Distilled water - 58.42g 1-Bromopentane 1-Pentanol Sodium Bromide Sulfuric Acid 1-Bromopentane Formula C5H12O NaBr H2SO4 C5H11Br MW (g/mol) 88.15 102.894 98.078 151.04 Density (g/mL) 0.811 3.21 1.84 1.218 Boiling point (*C) 138 1,396 337 130 NaBr(aq) + H2SO4(aq) -> NaHSO4(aq) + HBr(aq) CH3(CH2)4OH(aq) + H+ Br- (aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4Br(aq) + H2O(aq) How do I calculate the percent yield and identify the limiting reagent?Chloroform has ∆Hvaporization = 29.2 ??/??? and boils at 61.2 °C. What is the value of ∆Svaporization for chloroform?Plz o Asap...!
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…How to convert 4.76pm to um? Showing the work. 4.76pm x___________m x_____________ um =________________um How to convert 25.0mL to cL? Showing the work. 25.0mL x______________ x ___________ = ______________cL
