a. i. Convert the following from decimal to binary (please show workings) 123 - 50- 138- 200- 10- ii. Using the IP address and subnet mask shown write out the host address: 222.49.49.11 = 255.255.255.0 128.23.230.19 = 255.255.0.0 10.10.10.10 = 255.0.0.0 200.113.123.11 = 255.255.255.0 223.169.23.20 = 255.255.0.0

a. i. Convert the following from decimal to binary (please show workings) 123 - 50- 138- 200- 10- ii. Using the IP address and subnet mask shown write out the host address: 222.49.49.11 = 255.255.255.0 128.23.230.19 = 255.255.0.0 10.10.10.10 = 255.0.0.0 200.113.123.11 = 255.255.255.0 223.169.23.20 = 255.255.0.0

Principles of Information Security (MindTap Course List)

6th Edition

ISBN:9781337102063

Author:Michael E. Whitman, Herbert J. Mattord

Publisher:Michael E. Whitman, Herbert J. Mattord

Chapter6: Security Technology: Access Controls, Firewalls, And Vpns

Section: Chapter Questions

Problem 13RQ

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