a. What is the distribution of ? T - N( b. For the group of 14, find the probability that the average number of friends is more than 94. c. Find the first quartile for the average number of Facebook friends.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Suppose that the average number of Facebook friends users have is normally distributed with a mean of 111
and a standard deviation of about 59. Assume fourteen individuals are randomly chosen. Answer the following
questions. Round all answers to 4 decimal places where possible.
a. What is the distribution of æ? ¤ - N(
b. For the group of 14, find the probability that the average number of friends is more than 94.
c. Find the first quartile for the average number of Facebook friends.
d. For part b), is the assumption that the distribution is normal necessary?
Yes No
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Transcribed Image Text:Suppose that the average number of Facebook friends users have is normally distributed with a mean of 111 and a standard deviation of about 59. Assume fourteen individuals are randomly chosen. Answer the following questions. Round all answers to 4 decimal places where possible. a. What is the distribution of æ? ¤ - N( b. For the group of 14, find the probability that the average number of friends is more than 94. c. Find the first quartile for the average number of Facebook friends. d. For part b), is the assumption that the distribution is normal necessary? Yes No Submit Question logi F2 F5 3 R. T. *CO 8 7 6
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a.

Central limit theorem:

Based on central limit theorem, if the population is normally distributed then the sampling distribution is also normally distributed regardless of the sample size. If there is no information about the population, for sufficiently large sample size n≥30 sampling distribution of sample mean has the normal distribution.

Let x¯be the average number of Facebook friends users which follows normal distribution. The mean is 111 and standard deviation is 59. That is, μ=111,σ=59.

The mean of the sampling distribution is,

μx¯=μ=111

The standard deviation of the sampling distribution is,

σx¯=σn=5914=15.7684

Thus, the distribution of x¯ is x¯~N(111,15.7684).

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