Question
Asked Dec 12, 2019
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A 29.0 cm long spring is hung vertically from a ceiling and stretches to 37.5 cm when an 8.50 kg mass is hung from its free end.
 
(a)
Find the spring constant (in N/m).
 
(b)
Find the length of the spring (in cm) if the 8.50 kg weight is replaced with a 175 N weight.
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Expert Answer

Step 1

Given:

Initial length of the spring = 29.5 cm

Weight from the spring = 8.5 kg weight

Final length of the spring = 37.5 cm

Step 2

Calculating the spring co...

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Force applied on the spring, F = mg = 8.5kg x (9.8m/s')=83.3N Elongation in spring, x = 37.5cm – 29.5cm = 8cm = 0.08m Using relation, F = kx F 83.3N We can find the spring constant as, k== =1041.25N/ m 0.08m k=1041.25N/m

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Tagged in
SciencePhysics

Kinematics

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