Asked Nov 4, 2019

A 4.2-g bullet leaves the muzzle of a rifle with a speed of 340 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.77-m-long barrel of the rifle? 

check_circleExpert Solution
Step 1


m 4.2 gm
m 4.2x10 kg
v =340 m/s
u 0 m/s
s 0.77 m

Image Transcriptionclose

m 4.2 gm m 4.2x10 kg v =340 m/s u 0 m/s s 0.77 m

Step 2

According to Newton equation of motion

— и* + 2as
у? —и?
а-75064.9350 m/s?

Image Transcriptionclose

у? — и* + 2as у? —и? 2s (340)-(0) а: 2x0.77 а-75064.9350 m/s?

Step 3

Force on bu...

F =ma
F 4.2x10 x75064.9350
F 315.27 N

Image Transcriptionclose

F =ma F 4.2x10 x75064.9350 F 315.27 N


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