A/A · B/B · C/C · D/D · E/E × a/a·b/b · C/C · d/d · E/E The geneticist crosses the F1 with a recessive tester and classifies the progeny by the gametic contribution of the F1: A · B.C · D · E 316 a · b. C · d · E 314 А. В.С-d.E 31 a · b · C · D · E 39 A · b· C · d · E 130 а - В.С.D.E 140 A · b· C · D · E 17 a · B·C ·d · E 13 1000 The second cross of pure lines is A/A · B/B · C/C · D/D · E/E × a/a ·B/B• c/c • D/D • e/e. The geneticist crosses the F1 from this cross with a recessive tester and obtains А - В. С-D:Е а - В-с- D-e A · B· c · D · e а - В. С.D.E А - В. С.D:е а - В-с. D.E а - В. С-D:e A · B· c · D · E 243 237 62 58 155 165 46 34 1000
. A geneticist mapping the genes A, B, C, D, and E makes
two 3-point testcrosses. The first cross of pure lines is
A/A ⋅ B/B ⋅ C/C ⋅ D/D ⋅ E/E × a/a ⋅ b/b ⋅ C/C ⋅ d/d ⋅ E/E
The geneticist crosses the F1 with a recessive tester and
classifies the progeny by the gametic contribution of
the F1:
A ⋅ B ⋅ C ⋅ D ⋅ E 316
a ⋅ b ⋅ C ⋅ d ⋅ E 314
A ⋅ B ⋅ C ⋅ d ⋅ E 31
a ⋅ b ⋅ C ⋅ D ⋅ E 39
A ⋅ b ⋅ C ⋅ d ⋅ E 130
a ⋅ B ⋅ C ⋅ D ⋅ E 140
A ⋅ b ⋅ C ⋅ D ⋅ E 17
a ⋅ B ⋅ C ⋅ d ⋅ E 13
1000
The second cross of pure lines is A/A • B/B • C/C • D/D •
E/E × a/a • B/B • c/c • D/D • e/e.
The geneticist crosses the F1 from this cross with a
recessive tester and obtains
A ⋅ B ⋅ C ⋅ D ⋅ E 243
a ⋅ B ⋅ c ⋅ D ⋅ e 237
A ⋅ B ⋅ c ⋅ D ⋅ e 62
a ⋅ B ⋅ C ⋅ D ⋅ E 58
A ⋅ B ⋅ C ⋅ D ⋅ e 155
a ⋅ B ⋅ c ⋅ D ⋅ E 165
a ⋅ B ⋅ C ⋅ D ⋅ e 46
A ⋅ B ⋅ c ⋅ D ⋅ E 34
1000
The geneticist also knows that genes D and E assort
independently.
a. Draw a map of these genes, showing distances in
map units wherever possible.
b. Is there any evidence of interference?
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