A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular instant, it is moving with a speed of 5.05 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 58° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.170 T. (a)What is the magnitude of the magnetic force (in N) on the ion? (b)What is the magnitude of the ion's acceleration (in m/s2) at this instant?

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Asked Dec 3, 2019
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A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular instant, it is moving with a speed of 5.05 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 58° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.170 T.
 
(a)
What is the magnitude of the magnetic force (in N) on the ion?
 
(b)
What is the magnitude of the ion's acceleration (in m/s2) at this instant?
 
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Step 1

(a) write the expression for magnetic force

F Bqvsin
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F Bqvsin

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Step 2

Substitute the values

F = (.0170 T)(2e) (5.05x 10 m/s) sin (58°)
(0170 T)(2x16x101 C)(5.05x10° m/s)sin (58°)
=2.33 x 1013 N
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F = (.0170 T)(2e) (5.05x 10 m/s) sin (58°) (0170 T)(2x16x101 C)(5.05x10° m/s)sin (58°) =2.33 x 1013 N

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Step 3

(b) Write the expression...

F =ma
F
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F =ma F

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