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- How is a solid-state diode tested? Explain.What is the difference between a diode and rectifier?A load is connected in the Full Bridge rectifier circuit (Four Diodes). Usedtransformer primary voltage value is 220 V (rms). The transformer winding ratio is 1:10.Using the 0.7 V model of the diode,Load Rating: 7 K Ohmsa) How many % of conduction does each diode branch stay on?b) Find the average values of the load voltage.c) Find the average values of the load current.d) Find the effective value of the load voltage.e) Find the effective value of the load current.
- The secondary input voltage to a single phase diode bridge rectifier is 50V, 50Hz, and the load can be replaced by a resistance of value 20ohms (a) Sketch a well labelled circuit of the converter described above. (b) Sketch the waveforms for the input voltage, output voltage, output current, and output current (c) Derive an equation for average output voltage and calculate for output dc voltage (d) Calculate the ripple factor of the output voltage (e) Transformer utilization factor (h) How can the ripple be improvedA number of diodes rated at 1620 V each are to be connected in series in a rectifier circuit with a maximum voltage of 3000V. A de-rating factor of 15% is recommended. The maximum difference in leakage current of the diodes is given as 10mA , and the maximum difference in stored charge is 20µC. Calculate, 1) the number of diodes that must be used, 2) a suitable component value for the static equalization circuit; 3) a suitable component value for the dynamic equalization circuit.1. A single-phase, 120V, 50Hz supply is connected to a controlled half-wave thyristor rectifier and series R-L load consisting of a resistor R of 350 ohms and inductor L of 150mH. The thyristor firing angle is 65 degrees. Assume the diode and thyristor are ideal. i) calculate the dc load voltage VDC and the load dc current IDC. ii) briefly explain why a freewheeling diode is often connected in parallel to an R-L connected load in rectifier circuits
- In a 1-phase full wave bridge rectifier with Vs = Vm sin ωt, with R load & ideal diodes. The expression for the average value of the output voltage is 2Vm/π Select one: True FalseA schematic design of a full-wave bridge type power supply is given below. Provide the appropriate values for the inductors, diodes, capacitor and resistors, such that the output DC voltage is 6.2 V and the max. output power for the load resistance is 20 mW (percentage error for output voltage and output power is 2%). AC voltage source: Amplitude=311.13, Freq=60, DC offset= 0. For the rectifier part, choose diodes with an appropriate PIV rating. Show all the formulas and computations involved in acquiring the values for the inductors, diodes, capacitor and resistors. In choosing your Zener diode, consider the output voltage and the output current. Note that the output current should be the minimum Zener current. For the value of the series resistor RS, choose a lower value for less ripple but always consider the required output voltage. The ripple voltage peak-to-peak value should be less than or equal to 1% of the required output voltage. Use the formula below for choosing the value…A single-phase full-wave rectifier uses a power transformer whose secondary voltage is 220V r.m.s. The load resistor is 100kΩ. Neglect the transformer losses and the forward drops in the diodes. Determine the following: DC output voltage 2. Ripple voltage
- Consider the full-wave rectifier circuit shown below, where• vS(t) is a sinusoidal signal with a peak value (Vs = 5 V).• Diodes are modelled using constant voltage model with VDO = 0.7 V• The ac line voltage has an rms value of 120 V and a frequency (f) = 60 Hza) Calculate the transformer turns ratio. b) Plot in the same graph signal vS(t) and the output signal vO(t) versus time (t) (show all details including amplitudes, time instances, etc.) c) Calculate the rms value of the output signal vO(t). (hint: sin2(x) = 0.5(1- cos(2x))) d) If a capacitor C=3.58 F is connected across R = 10 k, repeat (b) in a new graphA fully controlled three-phase rectifier bridge circuit supplies a dc load of 300V,60A, from 415V 3-phase ac supply via delta-star transformer. (i) Determine the required thyristor and transformer specifications. (ii) Draw the load and thyristor voltages when firing angle alpha = 60°. (ii) If a commutating diode is placed across the load, determine the FWD specification and then calculate the average load voltage and FWD average current when firing angle alpha = 45°4)Mark the correct statements: a) The frequency at the output of a half-wave rectifier circuit is 30 Hzb) The frequency at the output of a full-wave rectifier circuit is 60 Hz.c) To calculate the average voltage (DC) at the output of a full wave rectifier we use the formula: Ucc = 0.636 * Up.d) When using a bridged full wave rectifier, we know that the loss at the depletion barrier will be 2 * 0.7 Volts.e) None of the statements is correct.