According to a Wakefield Research survey of adult women, 50% of the women said that they had tried five or more diets in their lifetime (USA TODAY, June 21, 2011). Suppose that this result is true for the current population of adult women. A random sample of 11 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in this sample of 11 who had tried five or more diets in their lifetime is a. at most 7 The absolute tolerance is +0.0005. ces. P(at most 7) b. 4 to 6

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According to a Wakefield Research survey of adult women, 50% of the women said that they had tried five or more diets in their
lifetime (USA TODAY, June 21, 2011). Suppose that this result is true for the current population of adult women. A random sample of
11 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in
this sample of 11 who had tried five or more diets in their lifetime is
a. at most 7
The absolute tolerance is +0.0005. ces.
P(at most 7)
b. 4 to 6
Transcribed Image Text:According to a Wakefield Research survey of adult women, 50% of the women said that they had tried five or more diets in their lifetime (USA TODAY, June 21, 2011). Suppose that this result is true for the current population of adult women. A random sample of 11 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in this sample of 11 who had tried five or more diets in their lifetime is a. at most 7 The absolute tolerance is +0.0005. ces. P(at most 7) b. 4 to 6
Expert Solution
Step 1

From the provided information,

Sample size (n) = 11

50% of the women said that they had tried five or more diets in their lifetime that is probability of success (p) = 0.50

The process will follow binomial distribution as follow:

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