According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that at least five of the six M&M’s are yellow. If you repeatedly select random samples of six peanut M&M’s, on average how many do you expect to be yellow? (Round your answer to two decimal places.) yellow M&M’s With what standard deviation? (Round your answer to two decimal places.) yellow M&M’s
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that at least five of the six M&M’s are yellow.
If you repeatedly select random samples of six peanut M&M’s, on average how many do you expect to be yellow? (Round your answer to two decimal places.)
yellow M&M’s
With what standard deviation? (Round your answer to two decimal places.)
yellow M&M’s
Solution:
Let X be the number of peanut M and M 's are yellow.
The probability of peanut M and M 's are yellow is p= 0.15
n= 6 random sample of peanut.
The random variable X has binomial distribution with parameters n= 6 and p= 0.15
The formula for binomial distribution is
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