Acetic acid, CH3CO2H, reacts with ethanol, C2H5OH, to form water and ethyl acetate, CH;CO2C2H5: C2H5OH(aq) + CH3CO2H(aq) CH3CO2C2H5(aq) + H20(aq). The equilibrium constant for this reaction with dioxane as a solvent is 4.0. What are the equilibrium concentrations for a mixture that is initially 0.15 M in CH3CO2H, 0.15 M in C2H$OH, 0.40 M in CH3CO2C2H5, and 0.40 M in H2O?

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter14: Chemical Equilibrium
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Problem 14.3QE: Describe a nonchemical system that is not in equilibrium, and explain why equilibrium has not been...
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Acetic acid, CH3CO2H, reacts with ethanol, C2H5OH, to form water and ethyl acetate,
CH;CO2C2H5: C2H50H(aq) + CH3CO,H(aq) = CH3CO2C,H5(aq) + H20(aq). The equilibrium
constant for this reaction with dioxane as a solvent is 4.0. What are the equilibrium concentrations
for a mixture that is initially 0.15 M in CH3CO2H, 0.15 M in C2H5OH, 0.40 M in CH3CO2C2H5,
and 0.40 M in H2O?
Transcribed Image Text:Acetic acid, CH3CO2H, reacts with ethanol, C2H5OH, to form water and ethyl acetate, CH;CO2C2H5: C2H50H(aq) + CH3CO,H(aq) = CH3CO2C,H5(aq) + H20(aq). The equilibrium constant for this reaction with dioxane as a solvent is 4.0. What are the equilibrium concentrations for a mixture that is initially 0.15 M in CH3CO2H, 0.15 M in C2H5OH, 0.40 M in CH3CO2C2H5, and 0.40 M in H2O?
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