ACTIVITY 1: DOT PRODUCT Directions: Calculate the dot product of the following vectors. Encircle the letter of the correct answer. 1. Vector A has magnitude 3, vector B has magnitude 4 and the angle between A and B is 60°. What is the value of A•B? А. 3 В. 5 С. 6 D. 10.39 2. Vector A has magnitude 3V2, vector B has magnitude 5 and the angle between A and B is 135°. What is the value of A•B? A. -15v2 В. -15 С. 15 D. 15v2

ACTIVITY 1: DOT PRODUCT Directions: Calculate the dot product of the following vectors. Encircle the letter of the correct answer. 1. Vector A has magnitude 3, vector B has magnitude 4 and the angle between A and B is 60°. What is the value of A•B? А. 3 В. 5 С. 6 D. 10.39 2. Vector A has magnitude 3V2, vector B has magnitude 5 and the angle between A and B is 135°. What is the value of A•B? A. -15v2 В. -15 С. 15 D. 15v2

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter6: Energy Of A System

Section6.3: The Scalar Product Of Two Vectors

Problem 6.3QQ: Which of the following statements is true about the relationship between the dot product of two...

See similar textbooks

Similar questions

(a) For what values of the angle between two vectors is their scalar product positive? (b) For what values of is their scalar product negative?
Find the angle between vectors for (a) D=(-3.0i-4.0j)m and A=(-3.0i+4.0j)m and (b) D=(2.0i+4.0j+K)m and B=(-2.0i+3.0j+2.0K)m .
1. A.) Find the scalar dot product and the angle between the vectors B.) Find the Vector cross product of AxB A = 2.00i + 3.00j + 1.00k B = -4.00i + 2.00j – 1.00k
1.) Find the dot product A∙ B and its angle of the given vectors: A = 10î - 4ĵ +7 k̂ and B = -2î +ĵ + 6k̂ . 2.) Given the vectors: A = 3î – 3ĵ + k̂ and B = 4î + 9ĵ + 2k̂, find the A x B by using determinant and component methods in calculating the cross product.
Two vectors have the following magnitude, A = 12.8 m and B = 7.1 m. Their vector product is: A⨯B = -3.4 m i + 11.7 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A⨯B| = AB sin(θ)
Two vectors have the following magnitude, A = 8.3 m and B = 10.5 m. Their vector product is: A⨯B = -3.7 m i + 7.5 m k.What is the angle (in degrees) between the vectors A and B? Hint: Use |A⨯B| = AB sin(θ)
Given the pair of vectors, A = (9.00î − 5.00ĵ ) and B =(−3.00î + 9.00ĵ ),use the definition of a scalar product to determine the following. (a) the scalar product (b) the angle between the vectors (Enter an answer between 0 and 180 degrees.) ° (c) the angle ? between the vector A and the +x axis (Enter an answer between 0 and 180 degrees.) ° (d) the angle ? between the vector B and the +y axis (Enter an answer between 0 and 180 degrees.) °
Problem 20: Assume you have two vectors, A = 7.1i + 3.9j and an unknown vector B with length 3.2. In this problem, you must assume that both components of B are positive, Bx > 0, and By > 0. Part (a) If the scalar product of these two vectors is A⋅B = 16.3, what is the x-component of the vector B? You may assume that Bx > 0. Part (b) What is the y-component of the vector B? Again, assume By > 0.
Compute for dot product and cross product for each of the following cases.Identify the units of each product.a. A = 12j + 8k m B = 4i – 2j + 3k mb. A = 5i + 3j m B = 7i – 12k N
Vector ?⃗has a magnitude of 75.0cm and points at 30° above the positive x-axis. Vector?⃗⃗has a magnitude of 95.0 cm and points along the negative x-axis. Determine the x and y components of the sum of these two vectors Determine the magnitude and direction of the sum of these two vectors. Determine the dot product of vectors ?⃗and ?⃗⃗(?⃗∙?⃗⃗). Determine the magnitude of the cross product (|?⃗×?⃗⃗|).
Two vectors in Cartisian coordinates have components A= (2,2,3) and B =(4,-1,7). What is the dot product of vector A with Vector B?
Two vectors have the following magnitude, A = 9.4 m and B = 8.5 m. Their vector product is: A⨯B = -4.4 m i + 14.3 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A⨯B| = AB sin(θ) Note: Bold face letters represents a vector.