Activity 2: Tell Me! Directions: Give what is asked in each item based on the situation. Write your answer on your answer sheet. A ball is thrown vertically upward. a. What is the acceleration of the ball after 1 s? b. What is the acceleration of the ball at its maximum height? c. What is the velocity of the ball at the top of its path?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 58P
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Solutions:
a.
v after is
use:
V₁ = V₁ - gt
vy=20 m/s-(9.8 m/s²)(1.0s)
vf= 20 m/s -9.8 m/s
vf = 10.2 m/s
b. v after 2s
use:
c. d after 1s
use:
v₁ = v₁ - gt
vy=20 m/s-(9.8 m/s²)(2.0s)
vf= 20 m/s - 19.6 m/s
vf = 0.4 m/s
d = v₁t -
912
2
d=20m/s(1.0s) - (9.8 m/s²)(1.0s)²
2
d=20m-4.9 m
d=15.1 m
(positive sign denotes that the object is
moving upward)
d. t from origin to maximum height
Note: An object thrown upward will
reach a certain point (maximum
height) where it will momentarily
stop and then start to move
downward. At this point, vy= 0.
V₁ = V₁ - gt
Use:
Manipulating the equation,
V₁ - Vf
9
t =
t=20 m/s-0
9.8 m/s²
t = 2.04 s
e. d from origin to maximum height
use:
d = v₁t
d=20m/s (2.04 s) - (9.8 m/s²)(2.04s)²
-
gt²
2
2
d = 40.8 m -20.40 m
d = 20.4 m
Transcribed Image Text:Solutions: a. v after is use: V₁ = V₁ - gt vy=20 m/s-(9.8 m/s²)(1.0s) vf= 20 m/s -9.8 m/s vf = 10.2 m/s b. v after 2s use: c. d after 1s use: v₁ = v₁ - gt vy=20 m/s-(9.8 m/s²)(2.0s) vf= 20 m/s - 19.6 m/s vf = 0.4 m/s d = v₁t - 912 2 d=20m/s(1.0s) - (9.8 m/s²)(1.0s)² 2 d=20m-4.9 m d=15.1 m (positive sign denotes that the object is moving upward) d. t from origin to maximum height Note: An object thrown upward will reach a certain point (maximum height) where it will momentarily stop and then start to move downward. At this point, vy= 0. V₁ = V₁ - gt Use: Manipulating the equation, V₁ - Vf 9 t = t=20 m/s-0 9.8 m/s² t = 2.04 s e. d from origin to maximum height use: d = v₁t d=20m/s (2.04 s) - (9.8 m/s²)(2.04s)² - gt² 2 2 d = 40.8 m -20.40 m d = 20.4 m
Activity 2: Tell Me!
Directions: Give what is asked in each item based on the situation. Write your answer on your
answer sheet.
A ball is thrown vertically upward.
a. What is the acceleration of the ball after 1 s?
b. What is the acceleration of the ball at its maximum height?
c. What is the velocity of the ball at the top of its path?
d. If the ball is thrown with an initial velocity of 50 m/s, what is the final
velocity of the ball at a point at the same level as when it was thrown?
e. What force was exerted on the ball 1 second after it was thrown?
f. What exerts this force?
g.
What is the acceleration of the ball 10 seconds after being thrown up?
h. If the ball took 5 s to reach its maximum height, how long will the ball
go back to where it was initially launched?
i. What is the acceleration of the ball at the top of its path?
j. What is the speed of the ball at the top of its path?
It's now time to check your learning from this module. Complete the statement.
Transcribed Image Text:Activity 2: Tell Me! Directions: Give what is asked in each item based on the situation. Write your answer on your answer sheet. A ball is thrown vertically upward. a. What is the acceleration of the ball after 1 s? b. What is the acceleration of the ball at its maximum height? c. What is the velocity of the ball at the top of its path? d. If the ball is thrown with an initial velocity of 50 m/s, what is the final velocity of the ball at a point at the same level as when it was thrown? e. What force was exerted on the ball 1 second after it was thrown? f. What exerts this force? g. What is the acceleration of the ball 10 seconds after being thrown up? h. If the ball took 5 s to reach its maximum height, how long will the ball go back to where it was initially launched? i. What is the acceleration of the ball at the top of its path? j. What is the speed of the ball at the top of its path? It's now time to check your learning from this module. Complete the statement.
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