Aditi titrated 80.00 mL of 0.50 Mmethylamine, CH3NH2, with 0.40 M HCI.CH3NH₂ Kb = 4.4 x 10-4What is the pH for the solution at theequivalence point of the titration?pH = [?]pH @ Equiv. PtEnter

Kb = 4.4×10-4 pKb = 3.36 Molarity of base =0.50 M Volume of base = 80 mL M × V Mmol of base =M × V…

Answered: Aditi titrated 80.00 mL of 0.50 M…

Aditi titrated 80.00 mL of 0.50 M ethylamine, CH3NH2, with 0.40 M HC CH3NH₂ Kb = 4.4 x 10-4 What is the pH for the solution at the equivalence point of the titration? pH = [?] pH @ Equiv. Pt Enter

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter19: Applications Of Standard Electrode Potentials

Section: Chapter Questions

Problem 19.13QAP

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Question

Aditi titrated 80.00 mL of 0.50 M
methylamine, CH3NH2, with 0.40 M HCI.
CH3NH₂ Kb = 4.4 x 10-4
What is the pH for the solution at the
equivalence point of the titration?
pH = [?]
pH @ Equiv. Pt
Enter

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