advanced chemistry lab, a student prepared solutions of 0.1 citric acid (H3C6H507), 0.1 M lactic acid (HC3H5O3) and 0.1 M suituric acid (H2S04). Onfortunately, this advanced student heglected to label the samples or these acids! But all is not lost! The student recognizes that one of these is a monoprotic, one is a diprotic, and the other a triprotic acid. To determine the identity of the solutions, he decided to titrate the acids with 0.0500 M NaOH. Use the data he collected for his fırst titration to determine the identity of that acid. Volume of Acid Titrated: 10.00 ml Molarity NaOH: 0.0500 M Final Buret Reading: 43.12 ml Initial Buret Reading: 2.98 m Volume of NaOH used This acid is
advanced chemistry lab, a student prepared solutions of 0.1 citric acid (H3C6H507), 0.1 M lactic acid (HC3H5O3) and 0.1 M suituric acid (H2S04). Onfortunately, this advanced student heglected to label the samples or these acids! But all is not lost! The student recognizes that one of these is a monoprotic, one is a diprotic, and the other a triprotic acid. To determine the identity of the solutions, he decided to titrate the acids with 0.0500 M NaOH. Use the data he collected for his fırst titration to determine the identity of that acid. Volume of Acid Titrated: 10.00 ml Molarity NaOH: 0.0500 M Final Buret Reading: 43.12 ml Initial Buret Reading: 2.98 m Volume of NaOH used This acid is
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 86AE
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