Advanced Math Question
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Expert Solution
Step 1
Prove that ∆ABC~∆A’B’C’, as follows:
- ∠BCA=∠B’C’A’ (Vertically Opposite Angles)
- ∠ABC=∠C’B’A’ (Interior alternate angles are equal for parallel lines AB and A’B’)
- ∠CAB=∠C’A’B’ (Interior alternate angles are equal for parallel lines AB and A’B’)
Therefore from the A.A.A. (Angle-Angle-Angle) axiom of similarity, triangle ABC is similar to ∆A’B’C’, or:
∆ABC~∆A’B’C’ (A.A.A.)
Step 2
Since ∆ABC~∆A’B’C’, therefore:
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