y“+2y/ – 3y = et y(0) = 1, y/ (0) = -1 - a. f(t) = et + e3t + fte + 음et + tte 16 6. 16 b.f(t) = cf0) = #te'+ 음et + te 16 c.f(t) 6. 16 %3D 16 d. f(t) = 16te' + 16 -3t le

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