After falling from rest from a height of 31 m, a 0.40-kg ball rebounds upward, reaching a height of 21 m. If the contact between ball and ground lasted 2.3 ms, what average force was exerted on the ball? (Enter the magnitude.)

Physics for Scientists and Engineers: Foundations and Connections
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Chapter10: Systems Of Particles And Conservation Of Momentum
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Problem 65PQ: A racquetball of mass m = 43.0 g, initially moving at 30.0 m/s horizontally in the positive x...
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After falling from rest from a height of 31 m, a 0.40-kg ball rebounds upward, reaching a height of 21 m. If the contact between ball and ground lasted 2.3 ms, what average force was exerted on the ball? (Enter
the magnitude.)
N
Transcribed Image Text:After falling from rest from a height of 31 m, a 0.40-kg ball rebounds upward, reaching a height of 21 m. If the contact between ball and ground lasted 2.3 ms, what average force was exerted on the ball? (Enter the magnitude.) N
Expert Solution
Step 1

The velocity of ball when it touches the ground after falling from height 31 m is given as 

V² = u²-2ah             

Where V is velocity when it hit ground

u is velocity ag start of event that ie 0

a = -g ,, acceleration due to gravity

h height of ball at starting point 

So...

V² = 2gh = 2(9.8)(31)

V = 24.65 m/s.... downward direction

 

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