Question
Asked Nov 4, 2019

After falling from rest from a height of 31 m, a 0.60-kg ball rebounds upward, reaching a height of 21 m. If the contact between ball and ground lasted 2.5 ms, what average force was exerted on the ball? 

check_circleExpert Solution
Step 1

Assume that the velocity in downward direction is negative and in upward direction is positive.

 Velocity of the ball as it strikes the ground is

2gh
2(9.8)(31)
24.64m/s
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2gh 2(9.8)(31) 24.64m/s

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Step 2

Velocity of the ball as it just ...

2= 2gH
2(9.8)(21)
=20.28 m/s
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2= 2gH 2(9.8)(21) =20.28 m/s

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Kinematics

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