After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 46.0 cm. The explorer finds that the pendulum completes 98.0 full swing cycles in a time of 145 s. What is the magnitude of the gravitational acceleration on this planet? Express your answer in meters per second per second gPlanet=(?)m/s^2

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 46.0 cm. The explorer finds that the pendulum completes 98.0 full swing cycles in a time of 145 s. What is the magnitude of the gravitational acceleration on this planet? Express your answer in meters per second per second gPlanet=(?)m/s^2

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom

Section: Chapter Questions

Problem 6OQ: Suppose the gravitational acceleration at the surface of a certain moon A of Jupiter is 2 m/s2. Moon...

See similar textbooks

Similar questions

Suppose the gravitational acceleration at the surface of a certain moon A of Jupiter is 2 m/s2. Moon B has twice the mass and twice the radius of moon A. What is the gravitational acceleration at its surface? Neglect the gravitational acceleration due to Jupiter, (a) 8 m/s2 (b) 4 m/s2 (c) 2 m/s2 (d) 1 m/s2 (e) 0.5 m/s2
When the Earth passes a planet such as Mars, the planet appears to move backward for a time, a phenomenon known as retrograde motion. Ancient astronomers believed that the Earth did not move and that the planets moved around the Earth. They also believed that uniform circular motion was perfect and that heavenly objects such as planets exhibited this perfect motion. How do you suppose ancient astronomers accounted for retrograde motion? Include a sketch with your explanation.
In this problem, you are going to explore three different ways to determine the gravitational constant G. a) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.66 × 10-3 m/s2, what is the gravitatonal constant G, in cubic meters per kilogram per square second? Assume the Earth has a mass of ME = 5.96 × 1024 kg, and the mean distance between the centers of the Earth and Moon is rm = 3.81 × 108 m. b) Measuring the centripetal acceleration of an orbiting object is rather difficult, so an alternative approach is to use the period of the orbiting object. Find an expression for the gravitational constant in terms of the distance between the gravitating objects rm, the mass of the larger body (the earth) ME, and the period of the orbiting body T. c) The gravitational constant may also be calculated by analyzing the motion of an object, launched from the surface of the earth at an initial velocity of vi. Find an expression of the gravitational constant…
An exoplanet (JB-2285), located in the galaxy closest to ours, uses a system where the units of mass and force are phljmth and xwyflr. respectively. Xwyflr is defined as the unit of force required to accelerate a unit mass, phljmth, with the gravitational acceleration (in m/s2) on the surface of the exoplanet which is seven tenths of the gravitational acceleration on earth’s surface (9.8066 m/s2). a. What is the conversion factor to convert a force in xwyflr to force in phljmth●m/s2? b. Calculate the weight in xwyflr of a 14.28 phljmth object on the surface of the exoplanet JB-2285. c. Determine the weight of the object in (b) in Newtons (N) in Mintal, Davao City if 137.224 N = 1.00 xwyflr? d. What is the mass in grams of a 796.2-phljmth object?
In this problem you will measure the gravitational constant in a series of “observational experiments,” making use of Newton’s law of gravitation and second law of motion as well as Kepler’s third law of planetary motion Suppose a rocket is launched as described in part (d) with an initial speed of vi = 494 m/s and attains a peak altitude of H = 12.7 km above the surface of Earth. Taking ME = 5.95×1024 kg and Ri = 6.41×106 m, what is the measured value of the gravitational constant, in units of N⋅m2/kg2?
The mean diameters of Mars and Earth are 6.9×10^3km and1.3×10^4km, respectively. The mass of Mars is 0.11 timesEarth's mass [Mass of Earth = 5.98×10^24kg]. What is: a)The ratio of the mean density (mass per unit volume) of Mars to that of Earth? b)The value of the gravitational acceleration on Mars? c)The escape speed on Mars?
The dwarf planet Pluto has a radius of 1.15 x 10^6 m and a mass of 1.2x10^22 kg . What is the value of g on the surface of Pluto?
The radius of the Earth R_{E} = 6.378 * 10 ^ 6 m and the acceleration due to gravity at its surface is 9.81m / (s ^ 2) Calculate the altitude above the surface of earth in meters , at which the acceleration due to gravity is g= 1.2 m/s^2
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational field strength of Planet X? The gravitational field strength of Planet X is mg. The gravitational field strength of Planet X is Wx/m. The gravitational field strength of Planet X is 9.8 N/kg. The gravitational field strength of Planet X is mWx.
An object’s average density r is defined as the ratio of its mass to its volume: r = M/V. The earth’s mass is 5.94 * 1024 kg, and its volume is 1.08 * 1012 km3. What is the earth’s average density?A. 5.50 * 103 kg/m3 B. 5.50 * 106 kg/m3 C. 5.50 * 109 kg/m3 D. 5.50 * 1012 kg/m3
The highest mountain in Canada is Mount Logan with a peak height of 5959 m above sea level Assume that sea leveldefines the height of Earth’s surface. (rE = 6.38 x 10^6m, mE = 5.98 x 10^24 kg, G = 6.67 x 10^−11N ∙ m2/kg2)a) Calculate the strength of Earth’s gravitational field at the altitude of Mount Logan. b) What is the ratio of the strength of Earth’s gravitational field at the top of Mount Logan to the strength of the Earth’ssurface? c) A mountain climber on top of Mount Logan wonders how fast must a satellite leave Earth’s surface to reach an orbitwith an altitude 800 km above his position. Calculate the velocity of the satellite.
One of the first things you learn in physics class is the law of universal gravitation, F = G (m1m2 /r2 ), where F is the attractive force between two bodies, m1 and m2 are the masses of the two bodies, r is the distance between the two bodies, and G is the universal gravitational constant equal to (6.67428 ± 0.00067) × 10−11 [the units of G are not given here]. (a) Calculate the SI units of G. For consistency, give your answer in terms of kg, m, and s. (b) Suppose you don’t remember the law of universal gravitation, but you are clever enough to know that F is a function of G, m1, m2, and r. Use dimensional analysis and the method of repeating variables (show all your work) to generate a nondimensional expression for F = F(G, m1, m2, r). Give your answer as Π1 = function of (Π2, Π3, …). (c) Dimensional analysis cannot yield the exact form of the function. However, compare your result to the law of universal gravitation to find the form of the function