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A₂H.(g) + 6 X₂(g) → 2 AX,(g) + 6 HX(g) A and X are unknown elements. When the reaction given above is carried out in a constant pressure (1 atm) container, some heat is evolving and 68.48 L increase in volume is observed. The same reaction is carried out with the same amounts but this time in a constant volume container 402.12 kJ heat is released. Using this information and given reactions calculate the molar sublimation enthalpy of H,AO, in kJ at 298 K. ½H₂(g) + ½ X₂(g) → HX(g) ΔΗ = -92.3 kJ AX₂(g) + 3 H₂O(1)→ H,AO₂(g) + 3 HX(g) AH = -112.5 kJ A₂H₂(g) + 6 H₂O(l) → 2 H₂AO,(s) + 6 H₂(g) AH = -493.4 kJ

A₂H.(g) + 6 X₂(g) → 2 AX,(g) + 6 HX(g) A and X are unknown elements. When the reaction given above is carried out in a constant pressure (1 atm) container, some heat is evolving and 68.48 L increase in volume is observed. The same reaction is carried out with the same amounts but this time in a constant volume container 402.12 kJ heat is released. Using this information and given reactions calculate the molar sublimation enthalpy of H,AO, in kJ at 298 K. ½H₂(g) + ½ X₂(g) → HX(g) ΔΗ = -92.3 kJ AX₂(g) + 3 H₂O(1)→ H,AO₂(g) + 3 HX(g) AH = -112.5 kJ A₂H₂(g) + 6 H₂O(l) → 2 H₂AO,(s) + 6 H₂(g) AH = -493.4 kJ

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.43QE: Another reaction that is used to propel rockets is N2O4(l)+2N2H4(l)3N2(g)+4H2O(g) This reaction has...
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A₂H.(g) + 6 X₂(g) → 2 AX,(g) + 6 HX(g) A and X are unknown elements. When the reaction given above is carried out in a constant pressure (1 atm) container, some heat is evolving and 68.48 L increase in volume is observed. The same reaction is carried out with the same amounts but this time in a constant volume container 402.12 kJ heat is released. Using this information and given reactions calculate the molar sublimation enthalpy of H₂AO, in kJ at 298 K. ½ H₂(g) + 2 X₂(g) → HX(g) AH = -92.3 kJ AX₂(g) + 3 H₂O(1)→ H₂AO₂(g) + 3 HX(g) AH = -112.5 kJ A₂H.(g) + 6 H₂O(1)→ 2 H₂AO,(s) + 6 H₂(g) AH = -493.4 kJ
Transcribed Image Text:A₂H.(g) + 6 X₂(g) → 2 AX,(g) + 6 HX(g) A and X are unknown elements. When the reaction given above is carried out in a constant pressure (1 atm) container, some heat is evolving and 68.48 L increase in volume is observed. The same reaction is carried out with the same amounts but this time in a constant volume container 402.12 kJ heat is released. Using this information and given reactions calculate the molar sublimation enthalpy of H₂AO, in kJ at 298 K. ½ H₂(g) + 2 X₂(g) → HX(g) AH = -92.3 kJ AX₂(g) + 3 H₂O(1)→ H₂AO₂(g) + 3 HX(g) AH = -112.5 kJ A₂H.(g) + 6 H₂O(1)→ 2 H₂AO,(s) + 6 H₂(g) AH = -493.4 kJ
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