Air lows past an object and exits as a free jet as shown in the figure. Because of the obstruction, the exit velocity is non-uniform with magnitude of 4 m/s from r = 0 to r = 0.5 m and 12 m/s from r = 0.5 m/s to r = 1.0 m. It is initially calculated that the average velocity is 10 m/s, Using a differential area, dA = 2rdr, what is the value of the kinetic energy correction factor, a? Air -4 m/s 2-m-dia. Wake 1-m dia. -12 m/s Exit Answer:

Air lows past an object and exits as a free jet as shown in the figure. Because of the obstruction, the exit velocity is non-uniform with magnitude of 4 m/s from r = 0 to r = 0.5 m and 12 m/s from r = 0.5 m/s to r = 1.0 m. It is initially calculated that the average velocity is 10 m/s, Using a differential area, dA = 2rdr, what is the value of the kinetic energy correction factor, a? Air -4 m/s 2-m-dia. Wake 1-m dia. -12 m/s Exit Answer:

Name: Air lows past an object and exits as a free jet as shown in the figur
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Description: Air lows past an object and exits as a free jet as shown in the figure. Because of the obstruction, the exit velocity is non-uniform with magnitude of 4m/s from r = 0 to r = 0.5 m and 12 m/s from r = 0.5 m/s to r = 1.0 m. It is initially calculated

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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