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Alice and Bob decided to use HMAC to authenticate the communication between them. They already share a key k for the MAC scheme. To sign a message M (which is always of an even bit length), the sender parses the message as M=M_L||M_R, i.e. the message is parsed as a left half and a right half (both halves have equal length), then the sender computes X-M₁+MR (where denotes XOR). The sender then sends M and T=HMACK(X) to the other party. Does this construction provide existential unforgeability? O Yes No

Alice and Bob decided to use HMAC to authenticate the communication between them. They already share a key k for the MAC scheme. To sign a message M (which is always of an even bit length), the sender parses the message as M=M_L||M_R, i.e. the message is parsed as a left half and a right half (both halves have equal length), then the sender computes X-M₁+MR (where denotes XOR). The sender then sends M and T=HMACK(X) to the other party. Does this construction provide existential unforgeability? O Yes No

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Alice and Bob decided to use HMAC to authenticate the communication between them. They already share a key k for the MAC scheme. To sign a message M (which is always of an even bit length), the sender parses the message as M=M_L||M_R, i.e. the message is parsed as a left half and a right half (both halves have equal length), then the sender computes X-M₁MR (where denotes XOR). The sender then sends M and T=HMACK(X) to the other party. Does this construction provide existential unforgeability? Yes No
Transcribed Image Text:Alice and Bob decided to use HMAC to authenticate the communication between them. They already share a key k for the MAC scheme. To sign a message M (which is always of an even bit length), the sender parses the message as M=M_L||M_R, i.e. the message is parsed as a left half and a right half (both halves have equal length), then the sender computes X-M₁MR (where denotes XOR). The sender then sends M and T=HMACK(X) to the other party. Does this construction provide existential unforgeability? Yes No
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