8. b. What do the displayed Bonferroni results tell us?With a P-value oftherea significant difference between the No Treatment and Fertilizer groups.With a P-value oftherea significant difference between the No Treatment and Irrigation groups.With a P-value oftherea significant difference between the No Treatment and Fertilizer and Irrigation groups.(Round to three decimal places as needed.)c. Let µ4, H2, Hz, and H4 represent the mean amount of the no treatment, fertilizer, irrigation, and fertilizer and irrigation groups, respectively. Use the Bonferroni test procedure with a 0.10 significance level to test for a significant differencebetween the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and the P-value. What do the results indicate?Determine the null and alternative hypotheses.Ho:H1:The test statistic is(Round to two decimal places as needed.)Find the P-value.The P-value is(Round to three decimal places as needed.)What do the results indicate at a 0.10 significance level?O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight.B. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight.O C. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight.D. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight. The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from usingthe Bonferroni test with the sample data. Complete parts (a) through (c).Poplar Weights (kg) and Bonferroni Resultsa. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight.Determine the null and alternative hypotheses.No TreatmentFertilizerIrrigationFertilizer and IrHo:1.2140.9410.0720.849Hy:0.5680.8710.6591.7780.5620.4580.0991.465Determine the test statistic.0.1280.5820.8212.247The test statistic is1.3031.0310.9351.636(Round to two decimal places as needed.)Bonferroni ResultsDetermine the P-value.MeanDifference (I-J) | Std. Error- 0.0216(1) TREATMENT(J) TREATMENTSig.The P-value is1.002.000.269731.0003.000.23780.269731.000(Round to three decimal places as needed.)4.00- 0.84000.269730.040What is the conclusion for this hypothesis test at a 0.10 significance level?O A. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weighB. Reject Ho: There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.PrintDoneC. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.D. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.b. What do the displayed Bonferroni results tell us?With a P-value oftherea significant difference between the No Treatment and Fertilizer groups.With a P-value oftherea significant difference between the No Treatment and Irrigation groups.With a P-value oftherea significant difference between the No Treatment and Fertilizer and Irrigation groups.(Round to three decimal places as needed.)

Question

Accepted Answer

no treatment
fertilizers
irrigation 
fertilizers and irrigation

1.214
0.941
0.072
0.849

0.568…

alue of alue of alue of three decimal places as needed.) there a significant difference b there a significant difference E there a significant difference E 2. H3, and Ha represent the mean amount of the