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Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4AI( s) + 30 2( g) 2Al 20 3( s) Calculate AG° for this reaction, given that AG° f of aluminum oxide is -1576.4 kJ/mol. 2-3152.8 kJ/mol O -1576.4 kJ/mol O 3152.8 kJ/mol -788.2 kJ/mol 1576.4 kJ/mol

Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4AI( s) + 30 2( g) 2Al 20 3( s) Calculate AG° for this reaction, given that AG° f of aluminum oxide is -1576.4 kJ/mol. 2-3152.8 kJ/mol O -1576.4 kJ/mol O 3152.8 kJ/mol -788.2 kJ/mol 1576.4 kJ/mol

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.61QE: When 7.11 g NH4NO3 is added to 100 mL water, the temperature of the calorimeter contents decreases...
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Strong acid vs. weak base. Strong acid vs. strong base. QUESTION 16 Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4AI( s) + 30 2( g)→ 2Al 20 3( s) Calculate AG° for this reaction, given that AG° of aluminum oxide is -1576 4 kJ/mol. -3152.8kJ/mol 1576.4 kJ/mol 3152.8 kJ/mol O-788.2 kJ/mol O 1576.4 kJ/mol QUESTION 17 Calculate the pH at the equivalence point for the titration of 0.20 M HCI with 0.20 M NH 3 (K, = 1.8 x 10 -5). 5.12 7.00 2.87 11.12 4.98
Transcribed Image Text:Strong acid vs. weak base. Strong acid vs. strong base. QUESTION 16 Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4AI( s) + 30 2( g)→ 2Al 20 3( s) Calculate AG° for this reaction, given that AG° of aluminum oxide is -1576 4 kJ/mol. -3152.8kJ/mol 1576.4 kJ/mol 3152.8 kJ/mol O-788.2 kJ/mol O 1576.4 kJ/mol QUESTION 17 Calculate the pH at the equivalence point for the titration of 0.20 M HCI with 0.20 M NH 3 (K, = 1.8 x 10 -5). 5.12 7.00 2.87 11.12 4.98
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