Aluminum L=3 ft A=0.75 in.² E=10x10 psi 2f3ft- C Bronze L=4 ft A=0.25 in.² E = 12 x 10° psi 2 ft2 ft D

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter6: Introduction To Mechanical Properties
Section: Chapter Questions
Problem 8ETSQ
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The rigid bars AB and CD are supported by pins at A and D. The vertical
rods are made of aluminum and bronze. Determine the vertical displacement of the point where the force P=10 kips is applied. Neglect the weights of the members.

Aluminum
L= 3 ft
A = 0.75 in.2
E = 10 x 10° psi
B
Bronze
L=4 ft
A = 0.25 in.?
E = 12 x 10 psi
D
+2 ft+-2 ft -
Transcribed Image Text:Aluminum L= 3 ft A = 0.75 in.2 E = 10 x 10° psi B Bronze L=4 ft A = 0.25 in.? E = 12 x 10 psi D +2 ft+-2 ft -
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