Ammonia can be produced by the reaction of hydrogen gas and nitrogen gas, as shown below: N2(g) + 3H2(g) → 2NH3(g) Given that the standard free energy of formation of NH3 (g) is -104 kJ/mol at 298 K, calculate the equilibrium constant, K, at this temperature. To express an answer in exponential notation, use E to indicate the exponent. For example, 3.0 x 103 would be written, 3.0E3.

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter16: Thermodynamics
Section: Chapter Questions
Problem 35E: Given: P4(s)+5O2(g)P4O10(s)G298=2697.0kJ/mol 2H2(g)+O2(g)2H2O(g)G298=457.18kJ/mol...
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Ammonia can be produced by the reaction of
hydrogen gas and nitrogen gas, as shown
below:
N2(g) + 3H2(g) → 2NH3(g)
Given that the standard free energy of formation
of NH3 (g) is -104 kJ/mol at 298 K, calculate the
equilibrium constant, K, at this temperature. To
express an answer in exponential notation, use E
to indicate the exponent. For example, 3.0 x 103
would be written, 3.0E3.
Transcribed Image Text:Ammonia can be produced by the reaction of hydrogen gas and nitrogen gas, as shown below: N2(g) + 3H2(g) → 2NH3(g) Given that the standard free energy of formation of NH3 (g) is -104 kJ/mol at 298 K, calculate the equilibrium constant, K, at this temperature. To express an answer in exponential notation, use E to indicate the exponent. For example, 3.0 x 103 would be written, 3.0E3.
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