Ammonia production is one example of an industrial product. It is largely used for fertilizers. Since it has great significance, out of curiosity, please calculate (c) the standard Gibbs energy of the reaction in kJ/mol. kJ/mol. 4 sig. fig.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter13: Spontaneous Processes And Thermodynamic Equilibrium
Section: Chapter Questions
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N2(g) + H2(g) → NH3(g)
Ammonia production is one example of an industrial product. It is largely used for
fertilizers. Since it has great significance, out of curiosity, please calculate
(c) the standard Gibbs energy of the reaction in kJ/mol.
kJ/mol. 4 sig. fig.
Given:
Sm(NH3,g) = 192.45 J/K.mol
Sme (N2.g) = 191.61 J/K.mol
Sm(H2.g) = 130.68 J/K.mol
AfH (NH3,g) = -46.11 kJ/mol
Transcribed Image Text:N2(g) + H2(g) → NH3(g) Ammonia production is one example of an industrial product. It is largely used for fertilizers. Since it has great significance, out of curiosity, please calculate (c) the standard Gibbs energy of the reaction in kJ/mol. kJ/mol. 4 sig. fig. Given: Sm(NH3,g) = 192.45 J/K.mol Sme (N2.g) = 191.61 J/K.mol Sm(H2.g) = 130.68 J/K.mol AfH (NH3,g) = -46.11 kJ/mol
N2(g) + H2(g) → NH3(g)
Ammonia production is one example of an industrial product. It is largely used for
fertilizers. Since it has great significance, out of curiosity, please calculate
(b) the change in entropy of the surroundings (at 298 K) of the reaction by initially
calculating the enthalpy of formation of ammonia.
J/K.mol. 3 sig. figures.
AS surr
Given:
=
Sm(NH3,g) = 192.45 J/K.mol
Sm(N2.g) = 191.61 J/K.mol
Sm(H2.g) = 130.68 J/K.mol
AfH (NH3,g) = -46.11 kJ/mol
Transcribed Image Text:N2(g) + H2(g) → NH3(g) Ammonia production is one example of an industrial product. It is largely used for fertilizers. Since it has great significance, out of curiosity, please calculate (b) the change in entropy of the surroundings (at 298 K) of the reaction by initially calculating the enthalpy of formation of ammonia. J/K.mol. 3 sig. figures. AS surr Given: = Sm(NH3,g) = 192.45 J/K.mol Sm(N2.g) = 191.61 J/K.mol Sm(H2.g) = 130.68 J/K.mol AfH (NH3,g) = -46.11 kJ/mol
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