An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.40 mm. A 15.0-V potential difference these plates. (a) Calculate the electric field between the plates. 10.7 V kV/m (b) Calculate the surface charge density. 948 There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2 (c) Calculate the capacitance. 4.804 V pF (d) Calculate the charge on each plate. 72.06 pC

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.40 mm. A 15.0-V potential difference is applied to
these plates.
(a) Calculate the electric field between the plates.
10.7
V kV/m
(b) Calculate the surface charge density.
948
There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2
(c) Calculate the capacitance.
4.804
V pF
(d) Calculate the charge on each plate.
72.06
pC
Transcribed Image Text:An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.40 mm. A 15.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 10.7 V kV/m (b) Calculate the surface charge density. 948 There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2 (c) Calculate the capacitance. 4.804 V pF (d) Calculate the charge on each plate. 72.06 pC
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