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An aircraft seam requires 23 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 23% of all seams need reworking, what is the probability that a rivet is defective? Hint: This question essentially asks you to reverse the process that was shown in class. You are given that the chance that all 23 rivets are not defective (i.e., the seam is not defective) is 77%. So what is the chance that any one rivet is not defective? Then what is the chance that any one rivet is defective? (b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?

An aircraft seam requires 23 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 23% of all seams need reworking, what is the probability that a rivet is defective? Hint: This question essentially asks you to reverse the process that was shown in class. You are given that the chance that all 23 rivets are not defective (i.e., the seam is not defective) is 77%. So what is the chance that any one rivet is not defective? Then what is the chance that any one rivet is defective? (b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 50E: Flexible Work Hours In a recent survey, people were asked whether they would prefer to work flexible...
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An aircraft seam requires 23 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 23% of all seams need reworking, what is the probability that a rivet is defective? Hint: This question essentially asks you to reverse the process that was shown in class. You are given that the chance that all 23 rivets are not defective (i.e., the seam is not defective) is 77%. So what is the chance that any one rivet is not defective? Then what is the chance that any one rivet is defective? (b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?
Transcribed Image Text:An aircraft seam requires 23 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 23% of all seams need reworking, what is the probability that a rivet is defective? Hint: This question essentially asks you to reverse the process that was shown in class. You are given that the chance that all 23 rivets are not defective (i.e., the seam is not defective) is 77%. So what is the chance that any one rivet is not defective? Then what is the chance that any one rivet is defective? (b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?
Consider the system of components connected as in the accompanying picture. Components 1 and 2 are connected in parallel, so that subsystem works if and only if either 1 or 2 works; since 3 and 4 are connected in series, that subsystem works if and only if both 3 and 4 work. If components work independently of one another and P(component i works) = 0.82 for i = 1, 2 and = 0.69 for i= 3, 4, calculate P(system works). (Round your answer to four decimal places.) ان 3
Transcribed Image Text:Consider the system of components connected as in the accompanying picture. Components 1 and 2 are connected in parallel, so that subsystem works if and only if either 1 or 2 works; since 3 and 4 are connected in series, that subsystem works if and only if both 3 and 4 work. If components work independently of one another and P(component i works) = 0.82 for i = 1, 2 and = 0.69 for i= 3, 4, calculate P(system works). (Round your answer to four decimal places.) ان 3
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