An alpha particle (ααalpha), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of −3.45×10−3 V . The charge and the mass of an alpha particle are q_a = 3.20×10−19 C and m_a = 6.68×10−27 kg , respectively. a)What is the value of the change in potential energy, ΔU=U_f−U_i, of the alpha particle? b)What is the final velocity of the alpha particle, (vf)αv_af? c)If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)α=−2qαΔVmα−−−−−−√ where ΔV is measured in volts. To verify that this expression for (vf)α has the correct units of velocity, you need to perform some unit analysis. Begin by finding the equivalent of a volt in terms of basic SI units. What is a volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (C)? Express your answer using the symbols for the units meters, seconds, kilograms, and coulombs.

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter26: Electric Potential
Section: Chapter Questions
Problem 65PQ: Two 5.00-nC charged particles are in a uniform electric field with a magnitude of 625 N/C. Each of...
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An alpha particle (ααalpha), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of −3.45×10−3 V .

The charge and the mass of an alpha particle are q_a = 3.20×10−19 C and m_a = 6.68×10−27 kg , respectively.

a)What is the value of the change in potential energy, ΔU=U_f−U_i, of the alpha particle?

b)What is the final velocity of the alpha particle, (vf)αv_af?

c)If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that

(vf)α=−2qαΔVmα−−−−−−√

where ΔV is measured in volts. To verify that this expression for (vf)α has the correct units of velocity, you need to perform some unit analysis. Begin by finding the equivalent of a volt in terms of basic SI units. What is a volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (C)?
Express your answer using the symbols for the units meters, seconds, kilograms, and coulombs.
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